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2 years ago

15

PLEASE HELP ILL GIVE5 STARS HELP ASAP

1 answer:

Katen [24]2 years ago

8 0

Answer:

H+2

Step-by-step explanation:

Please mark brainliest

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You charge customers $18.75 for lube service, parts, and labor. Assuming you take one hour's labor at $15, and the parts cost $3

hram777 [196]

Let
T---------> <span>the tax rate on the parts in $

we know that
$18.75=$15+$3.50+$T
T=18.75-15-3.5
T=$0.25
so
$3.50----------> 100%
$0.25--------> x
x=0.25*100/3.50------> x=7.14%------> x=7.1%

the answer is
7.1%</span>

5 0

3 years ago

You take a random token from a bag that contains 44? red, 1414? green, and 66? blue tokens. What is the probability your token i

german

Answer:

11/381

Step-by-step explanation:

Not sure what the ? after each number means but I'm going to assume they aren't there

so we need find the number of tokens in all which is

44+1414+66=1524

P(red)=44/1524 now reduce giving P(red)=11/381

5 0

3 years ago

Read 2 more answers

1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h

alina1380 [7]

Answer: $(g,h)=(-2,2)$

Step-by-step explanation:

Given

Midpoint is $(-2,3)$

Endpoints are $G(g,4)$ and $H(-2,h)$

Mid point of any two point is given by

$x=\frac{x_1+x_2}{2}$

and $y=\frac{y_1+y_2}{2}$

So, $-2=\frac{g+(-2)}{2}$

$-4=g-2$

$g=-2$

Also

$3=\frac{4+h}{2}$

$6=4+h$

$h=2$

Therefore $(g,h)=(-2,2)$

4 0

3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

3 years ago

Should one divulge information given in confidence

pickupchik [31]

No you should not do that.

5 0

3 years ago