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allochka39001 [22]
3 years ago
11

Carla bought a crate of red and green apples for her bakery. The crate had 140 red apples, which were 40% of the apples in the c

rate. How many apples were in the crate?
Mathematics
2 answers:
xenn [34]3 years ago
8 0

Answer:

350

Step-by-step explanation:

Do 140/0.4=350

Andrew [12]3 years ago
6 0

Answer:

350 apples

Step-by-step explanation:

a = total number of apples in the crate

a* 40% = number of red apples

a * .40 = 140

Divide each side by .40

a * .40/.40 = 140/.40

a =350

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Answer:

Vc = (π/3)✓17 ≈ 4.12 ft³

Step-by-step explanation:

h = ✓(4²+1²)

h = ✓17

V = πr²h/3

V = π(1)²✓17/3

V = (π/3)✓17 ≈ 4.12

8 0
2 years ago
The pet store sells bags of pet food. There are four bags of cat food. 1/6 of the bags of food are cat food. How many bags of pe
nikklg [1K]
If 1/6 of the bags of pet food are cat food, then the other 5/6 is other pet food.
Since there are 4 bags that make up 1/6 of the food, multiplying 4 by 6 should get the answer. 4 x 6 = 24
6 0
3 years ago
Read 2 more answers
I really need help with this question ​
jenyasd209 [6]

Answer:

its a discrete graph

Step-by-step explanation:

hope this helps

5 0
3 years ago
5.Karen is thinking of a number. If she multiplies her number by −3 and then adds 6, she has −4 times the original number. What
alekssr [168]

-3x+6 = -4x

6 = -x

x = -6

check:

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5 0
2 years ago
Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
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