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Aleksandr-060686 [28]
3 years ago
15

Pleas help with geometry!!

Mathematics
1 answer:
erastova [34]3 years ago
4 0

Answer:

Angles X and Z are supplementary, so 180-105. The answer is 75

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Pls help i beg i will give brainlist and points
leonid [27]

Answer:

7. 1/10 or 10%

9.5/10

11.5/10

13.9/10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Each day Donna and Mary toss a coin to see who buys the other person coffee ​($2.34 a​ cup). One tosses and the other calls the
netineya [11]

Answer:

yes

Step-by-step explanation:

Each day Donna and Mary toss a coin to see who buys the other person coffee ​($2.34 a​ cup). One tosses and the other calls the outcome. If the person who calls the outcome is​ correct, the other buys the​ coffee; otherwise the caller pays. Assume that an honest coin is​ used, that Mary tosses the​ coin, and that Donna calls the outcome.

7 0
3 years ago
The volume of a cube is V=s3 , where s is the length of one edge of the cube. What is the edge length s for each cube?
PolarNik [594]

Answer:

s = \sqrt[3]{999} }

Step-by-step explanation:

V = s^3

Plug in the given volume.

999 = s^3

Take the third root of both sides to cancel out the ^3.

\sqrt[3]{999} } = s

4 0
3 years ago
Read 2 more answers
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
During the election for class president, 40% of the students voted for jennifer, and 60% of the students voted for kevin. 300 st
Sholpan [36]
120 students voted for Jennifer and 180 students voted for Kevin. 60 students voted more for Kevin than for Jennifer.
3 0
2 years ago
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