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3 years ago

Ill mark brainlist plss help

Mathematics

2 answers:

zaharov [31]3 years ago

6 0

Answer: 256

Step-by-step explanation:

never [62]3 years ago

5 0

The answer is 256 I hope you ace it

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Eight less than four times a number is less than 56. What are the possible values of that number?

Damm [24]

For this case we can algebraically rewrite the expression given as:

$8-4x$

Where:

x: Represents the unknown number

Subtracting 8 from both sides of the inequality we have:

$-4x$

Dividing between 4 on both sides of the inequality:

$-x$

We multiply by -1 on both sides taking into account that the sense of inequality changes:

$x> -12$

ANswer:

$x> -12$

4 0

4 years ago

Read 2 more answers

Will mark BRAINLIEST and give ALL OF MY POINTS!!! Pls help asappp!!!! Tysm!

sdas [7]

Answer:

$125
$65, $65, $65 -- they are all the same

Step-by-step explanation:

The quantity of food required for the two cats for one day is ...

(3/4 can) + (1/2 can) = (3/4 +2/4) can = 5/4 can

Then the cost per day for cat food is ...

$5/(3 cans) × (5/4 can/day) = $25/12 /day

We note that the cost for some number of days will be the product of this factor and the number of days, rounded up to the next higher $5.

1. The cost for 60 days is ...

(60 days)($25/12 /day) = $25 × 60/12 = $125

A 60-day supply of cat food costs $125.

2. A 29-day supply costs ...

(29 day) × $25/12 /day = $60 5/12, rounds up to $65 for 29 days

A 30-day supply costs ...

(30 day) × ($25/12 /day) = $62.50, rounds up to $65 for 30 days

A 31-day supply costs ...

(31 days) × ($25/12 /day) = $64 7/12, rounds up to $65 for 31 days.

These costs are all the same.

_____

3 cans last, on average, 2 2/5 days. That means some purchases of 3 cans will last for 2 days, and some will last for 3 days. It so happens that the purchase made to cover day 29 will also cover day 30 and day 31.

4 0

3 years ago

Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a

Bumek [7]

Answer:

0.381 is the probability that the number of drivers will be at most 18.

Step-by-step explanation:

We are given the following information in the question:

The number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20.

The Poisson distribution is the discrete probability distribution of the number of events occurring in a given time period, given the average number of times the event occurs over that time period.
The variance of Poisson distribution is equal to the mean of Poisson distribution.

a) P(number of drivers will be at most 18)

Formula:

$P(X =k) = \displaystyle\frac{\mu^k e^{-\mu}}{k!}\\\\ \mu \text{ is the mean of the distribution}$

$P( x \leq 18) =P(x=0) + P(x =1) + P(x = 2) + ... + P(x = 18)\\\\= \displaystyle\frac{20^0 e^{-20}}{0!} + \displaystyle\frac{20^1 e^{-20}}{1!} +...+ \displaystyle\frac{20^{18} e^{-20}}{18!}\\\\ = 0.381$