Answer:
k = 13 The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Hope this was Right
On a unit circle, 120 is in the second quadrant. the terminal line form a 60 degree angle with the negative part of the x axis, the x value is -1/2, and the y value is √3/2
tan120=(√3/2)/(-1/2)=-√3
Answer:
(x+7)(x-2)
Step-by-step explanation:
=x^2+5x-14
=x^2+(7-2)x-14
=x^2+7x-2x-14
=x(x+7)-2(x+7)
=(x+7)(x-2)
Answer:
The equation that can be used to find the distance (d), the train will travel in any number of minutes (m) is d=0.12m
Step-by-step explanation:
we know that
distance = 
From the table below
CASE 1:
When time is 5 minutes and distance is 0.6 miles
Speed = 
Speed =
speed = 0.12
CASE 2:
When time is 8 minutes and distance is 0.96 miles
Speed = 
Speed =
speed = 0.12
CASE 3:
When time is 11 minutes and distance is 1.32 miles
Speed = 
Speed = 
speed = 0.12
CASE 4:
When time is 14 minutes and distance is 1.68 miles
Speed = 
Speed = 
speed = 0.12
CASE 5:
When time is 17 minutes and distance is 2.04 miles
Speed = 
Speed =
speed = 0.12
CASE 6:
When time is 20 minutes and distance is 2.4 miles
Speed = 
Speed =
speed = 0.12
In all the cases we get the speed as 0.12
Hence the equation can be
d = 0.12 m
where d is the distance(in miles) and m is the time(in minutes)