<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,

Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF =
F
Putting the values in the formula,



Therefore, the total capacitive reactance of the circuit is 7.96 Ω.
It is equal. .21 ia the same as 21%
16 I think sorry if I’m wrong
The common difference is 11, you can see this because the number goes up by eleven each time.