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enot [183]
3 years ago
11

Explain how to solve this system algebraically

Mathematics
2 answers:
gulaghasi [49]3 years ago
4 0

Answer:

take the -12 to behind the equal and replace with 0 then solve the polynomial

garik1379 [7]3 years ago
4 0
4x-2y=-12.....I
2x-y=-6.......II

2x+6=y......iii

From eqn I
4x-2(2x-y)=-12
or,4x-4x+2y=-12
or,2y=-12
Y=-6

In eqn iii
2x+6=-6(y=-6)
or,2x=-12
X=-6
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Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source. The total capacitive reactance is _____.
muminat

<u>Answer</u>-

<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>

<u>Solution-</u>

Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.

The effective/equivalent capacitance of the circuit is,

C=20+30=50\ mF

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.

We know that,

X_c=\dfrac{1}{2\pi fC}

Where,

X_c = Capacitive Reactance (in Ω)

f = frequency (in Hz)

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Here given,

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C = 50 mF = 50\times 10^{-6} F

Putting the values in the formula,

X_c=\dfrac{1}{2\pi \times 400\times 50\times 10^{-6}}

X_c=\dfrac{10^{6}}{40000\pi}

X_c=7.96\ \Omega

Therefore, the total capacitive reactance of the circuit is 7.96 Ω.

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