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enot [183]
3 years ago
11

Explain how to solve this system algebraically

Mathematics
2 answers:
gulaghasi [49]3 years ago
4 0

Answer:

take the -12 to behind the equal and replace with 0 then solve the polynomial

garik1379 [7]3 years ago
4 0
4x-2y=-12.....I
2x-y=-6.......II

2x+6=y......iii

From eqn I
4x-2(2x-y)=-12
or,4x-4x+2y=-12
or,2y=-12
Y=-6

In eqn iii
2x+6=-6(y=-6)
or,2x=-12
X=-6
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Write the equation 2x - 3y = 6 in slope-intercept form. User: Write the equation for 5x + 2y = 3 in slope-intercept form.
evablogger [386]
Slope intercept form is: y=mx+b

So you take the first equation: 2x-3y=6 and you subtract the 2x from both sides and get: -3y= 2x+6

Then you take that equation: -3y= 2x+6 and divide -3 from both sides and get: y= -2/3x -2

So the equation 2x-3y=6 in slope intercept from is
y = -2/3x -2


Can you do the next one your self based on the one i did...?

(Scroll and check ⬇️ )


























Here ya go ;)

5x + 2y = 3 okay same steps as above you want to get the x on the other side so you subtract the 5x from both sides and get:

2y = 5x + 3

Then you want to get the y by its self so you divide the 2 from both sides so you get:

y = 5/2x +2/3

Now idk if your allowed to leave it like that (based on your teacher's preferance really) but if not you can simplfy your fractions and get:

y = 2.5x + 0.66

( i would leave the 2/3 and just leave it as y = 2.5x + 2/3 ) but you do you and i hope that helped you :)
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