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Margarita [4]
3 years ago
5

When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent? Θ' = negative pi over 6; s

ine and cosine are positive, tangent is negative. Θ' = 5 pi over 6; sine and tangent are positive, cosine is negative Θ' = pi over 6; sine is positive, cosine and tangent are negative Θ' = negative 5 pi over 6; sine is positive, cosine and tangent are negative
Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

Option C is correct.

Step-by-step explanation:

\theta=\frac{5\pi }{6}

We need to find reference angle and signs of sinФ, cosФ and tanФ

We know that \theta=\frac{5\pi }{6}radians is equal to 150°

and 150° is in 2nd quadrant.

So, Ф is in 2nd quadrant.

And In 2nd quadrant sine is positive, while cos and tan are negative

The reference angle Ф' is found by: π - Ф

=> Ф = 5π/6

so, Reference angle Ф' = π - 5π/6

Ф' = 6π - 5π/6

Ф' = π/6

So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.

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Answer:

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Step-by-step explanation:

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2 years ago
Solve for x: 8 (3x + 10) = 28x - 14 - 4x ​
Ierofanga [76]

Answer:

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2 years ago
A factory employs several thousand workers, of whom 35% are Hispanic. If the 17 members of the union executive committee were ch
Elza [17]

Answer:

as p decreases, sigma decreases.

Step-by-step explanation:

Given that 35%are hispanic. For a sample of 17 members

n = 17

p = 0.35

and the number of Hispanics on the committee would have the binomial distribution

a) Mean of X = E(x) = np = 17(0.35)\\= 5.95

b) Std dev X = \sqrt{npq} =\sqrt{5.95(0.65)} \\=1.9665

c) Here n =17 and p =0.1

Mean = 1.7\\\sigma = \sqrt{17(0.1)(0.9)} =1.234

d) When p = 0.01

Mean = 0.17\\\sigma = 0.410

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8 0
3 years ago
Find the coefficient:
guapka [62]

Answer:

1/3

Step-by-step explanation:

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3 years ago
Read 2 more answers
Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of theflagpoleat an angle of eleva
torisob [31]

Answer:

h = 15.163\ meters

Step-by-step explanation:

(Assuming the correct angles are 30° and 45°)

We can use the tangent relation of the angle of elevation to find two equations, then we can use these equations to find the height of the pole.

Let's call the initial distance of the boy to the pole 'x'.

Then, with an angle of elevation of 30°, the opposite side to this angle is the height of the pole (let's call this 'h') minus the height of the boy, and the adjacent side to the angle is the distance x:

tan(30) = (h - 1.5) / x

Then, with an angle of elevation of 45°, the opposite side to this angle is still the height of the pole minus the height of the boy, and the adjacent side to the angle is the distance x minus 10:

tan(45) = (h - 1.5) / (x - 10)

So rewriting both equations using the tangents values, we have that:

0.5774 = (h - 1.5) / x

1 = (h - 1.5) / (x - 10) \rightarrow (h - 1.5) = (x - 10)

From the first equation, we have that:

x = (h - 1.5) / 0.5774

Using this value of x in the second equation, we have that:

h - 1.5 =  \frac{ (h - 1.5) }{0.5774} - 10

h + 8.5 =  \frac{ (h - 1.5) }{0.5774}

0.5774h + 4.9079 = h - 1.5

0.4226h = 6.4079

h = 15.163\ meters

5 0
3 years ago
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