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3 years ago

Evaluate the formula V= Bh/3 for B = 15 in.2 and h = 28 in.

Mathematics

2 answers:

Gelneren [198K]3 years ago

7 0

V=140in.^3 would be the answer

ad-work [718]3 years ago

6 0

V = Bh/3
V = 15 x 28 / 3
V = 420 / 3
V = 140 in^3

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Maslowich

you divide 12 by 25 which is 0.48 and multiply it by 48 and the answer is 48%

4 0

3 years ago

HELP NEEDED ASAP<br> image below

xxTIMURxx [149]

The amount of pounds of vegetable needed in fractions to make the stew exactly 10 pounds is 3 3 / 8 pounds

<h3>How to solve fractions?</h3>

The amount of pounds of vegetable needed to make the stew exactly 10 pounds can be calculated as follows:

potatoes weight = 2 7 / 8 pounds = 23 / 8 pounds

green beans weight = 1 1 / 4 = 5 / 4 pounds

pepper weight = 2 1 / 2 = 5 / 2 pounds

Therefore,

weight needed = 10 - 23 / 8 - 5 / 4 - 5 / 2

weight needed = 80 - 23 - 10 - 20 / 8

weight needed = 80 - 53 / 8

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learn more on fractions here: brainly.com/question/27894307

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2 years ago

What is the equation in point-slope form of the line passing through (−2, 0) and (2, 8)? (1 point) y = 2(x + 2) y = 2(x − 2) y =

Sonja [21]

Answer: $y=2(x+2)$

Step-by-step explanation:

The slope of the line is

$y=\frac{8-0}{2-(-2)}=\frac{8}{4}=2$

Using the point (-2, 0) to substitute into point-slope form, we get the equation to be $\boxed{y=2(x+2)}$

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1 year ago

A college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after th

Citrus2011 [14]

Answer:

Value of k is $\displaystyle\frac{3}{8}$

Step-by-step explanation:

We are given the following information in the question:

$f(x) = kx^2, 0\leq x \leq 2\\~~~~~~~= 0, \text{ otherwise}$

where x is the time elapses between the end of the hour and the end of the lecture.

We have to find the values of k.

Since, f(x) is the pdf, then,

$\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}$

Hence, value of k is $\displaystyle\frac{3}{8}$

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2 years ago

Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two

Damm [24]

Answer:

Step-by-step explanation:

Let S be the set of all graphs having vertex set \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

8 0

3 years ago