According to the given, 1 in every 10 women has been a victim, therefore the probability of a victim of domestic abuse at some pint is
We need to use Binomial distribution to take a randomly sampled of 25 women and asked each whether she has been a victim.
Where x is the event that shows a victim of domestic abuse at some point.
We need to find the probability of these victim at least 2 has been victim of abuse, so
![P(x>=2) = 1- [P(x=0)+P(x=1)]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201-%20%5BP%28x%3D0%29%2BP%28x%3D1%29%5D)
![P(x>=2) = 1 - [^{25}C_0(0.10)^0(1-0.10)^{25-0}+^{25}C_1(0.10)^1(1-0.10)^{25-1}]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201%20-%20%5B%5E%7B25%7DC_0%280.10%29%5E0%281-0.10%29%5E%7B25-0%7D%2B%5E%7B25%7DC_1%280.10%29%5E1%281-0.10%29%5E%7B25-1%7D%5D)
![P(x>=2) = 1 - [0.07198+0.199]](https://tex.z-dn.net/?f=P%28x%3E%3D2%29%20%3D%201%20-%20%5B0.07198%2B0.199%5D)
So the probability is 0.729
This means that
+- 6 < √42 < +- 7
hope it helps
Answer:
"How often do you seek medical information online?"
Of 1072 Internet users who chose to respond, 38% of them responded with "frequently."
The respondents here are voluntary response sample and are a self-selected sample.
The thing that is wrong here, it that it is possible that many people read the survey but may choose not to respond and also the few responses will not reflect the opinions of all the population.
