Https://www.symbolab.com/solver/algebra-calculator/x%2By%3Dz%3Bx
Can you post the image because I need to clarify in your trigonometry hw
<u>44%</u>
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
Answer:
x = 1
Step-by-step explanation:
-2x + y = 4
y = 2x + 4
2x + 3y = 20
2x + 3(2x + 4) = 20
2x + 6x + 12 = 20
8x + 12 = 20
8x = 8
x = 1
This one.
The doubly-shaded area is the solution set. The dashed line is not included.
