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finlep [7]
3 years ago
14

Hurry please... First correct answer gets brainliest

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0
It’s it’s it’s it’s it’s it’s it’s it’s it’s it’s is bbbbbbbbbbbbbbbbb
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Consider functions f and g
alexdok [17]

Answer:

A

Step-by-step explanation:

f(x) = \dfrac{x - 16}{x^2 + 6x - 40}

g(x) = \dfrac{1}{x + 10}

f(x) + g(x) =  \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{1}{x + 10}

f(x) + g(x) =  \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{(x - 4)}{(x + 10)(x - 4)}

f(x) + g(x) =  \dfrac{x - 16 + x - 4}{x^2 + 6x - 40}

f(x) + g(x) =  \dfrac{2x - 20}{x^2 + 6x - 40}

Answer: A

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2 years ago
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Ron would need to run 3 miles

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worty [1.4K]
<span>The one addend technique is the act of breaking up numbers to make even tens. 22+49 can be broken up into 21+49+1 and then added to make 21+50 and then these numbers can be more easily added to make 71.</span>
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