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3 years ago

Expression equivalent to 5(3m + n)

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

5(3m + n) = 15m + 5n

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Element X is a radioactive isotope such that every 61 years, its mass decreases by half. Given that the initial mass of a sample

Sever21 [200]

Answer:

27.3

Step-by-step explanation:

y=a(1/2)^t/h

Plug in

22=30(1/2)^t/61

Divide both sides by 30

0.7333333333=(1/2)^t/61

Log both

Log(0.7333333333) / Log(1/2)

0.447458977 = t/61

0.447458977 x 61 = t

27.2949976 to the nearest tenth is 27.3 = t

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3 years ago

What is 0.214 repeating as a fraction

Natalka [10]

214/1000 is this as a fraction

3 0

4 years ago

What is the volume of a prism where the base is a 45-45-90 triangle with a leg of 5 in. when the height is 1.8 in.?

Basile [38]

V = 22.5 cu in

V = (1/2)(5)(5)1.8)

Hope this helps!

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3 years ago

Which of these choices show a pair if equivelent expressions? Chack all that apply

Gwar [14]

Answer:

A. $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

D. $8^{\frac{9}{2}}\ and\ (\sqrt{8})^9$

Step-by-step explanation:

Equivalent expressions are those expressions that simplify to same form.

Now, let us check each of the given options.

Option A:

$(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

We know that,

$\sqrt[n]{x} =x^{\frac{1}{n}}$

Therefore, $\sqrt[3]{125} =(125)^{\frac{1}{3}}$

Thus the first expression becomes;

$((125)^{\frac{1}{3}})^9$

Now, using law of indices $(a^m)^n=a^{m\times n}$ , we get

$((125)^{\frac{1}{3}})^9=((125))^{\frac{1}{3}\times 9}=((125))^{\frac{9}{3}$

Therefore, $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$ are equivalent.

Option B:

$12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$

Consider the second expression $(\sqrt{12})^7$

We know that,

$\sqrt x=x^{\frac{1}{2}}$

$(\sqrt{12})^7=((12)^{\frac{1}{2}})^7=(12)^{\frac{1}{2}\times 7}=(12)^{\frac{7}{2}}$

Therefore, $12^{\frac{2}{7}} \ne (12)^{\frac{7}{2}}$ . Hence, the expressions $12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$ are not equivalent.

Option C:

$4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$

We know that,

$x^{\frac{1}{n}}=\sqrt[n]{x}$

Therefore, $4^{\frac{1}{5}}=\sqrt[5]{4}$

Now, $\sqrt[5]{4}\ne (\sqrt 4)^5$

Therefore, the expressions $4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$ are not equivalent.

Option D:

$8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$

Using law of indices $a^{m\times n}=(a^m)^n$ , we get

$8^{\frac{9}{2} }=(8^{\frac{1}{2}})^9$

Now, we know that, $x^{\frac{1}{2}}=\sqrt x$

So, $(8^{\frac{1}{2}})^9=(\sqrt8)^9$

Therefore, $8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$ are equivalent.

8 0

3 years ago

Compare the value of the 7 in 503,497 and 26,475

Feliz [49]

The value 7 in 26,475 is 10 times larger than 503,497

7 0

3 years ago