Answer:
It definitely seems right, so you should be good!
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Hope This Helped!</u></h2>
Notice that for this question, they are providing you with:
1) The slope of the line (4)
2) a point on the plane through which the line goes (6, -2)
So you can directly use for this the "point-slope" form of a line which is as follows:

This includes m as the slope, and the pair (x0, y0) as the pair representing the point the line goes through.
So, let's use the info they gave you to complete this:

which we can work out a little more:

And even a little more to finish the equation of the line in its standard slope-intercept form:

So the equation of the line is:
Answer:
20-8. 3. 4x+(5-3y), when r = 5 and y=-1. 415)+(5-3(-1). 20+ (5+3). 4. -7x-(-4x² ... 3. 3(3x - 1)-11x-1. 9X-3-11X-1. 4. -2(x - 5) +3(-4-). -2x+10-12-3x. [-5x-2. 5. 4-2(x +5)+3x(x - 2). H-2X-10+3x2-6X. [3x²8x-61. 6. 15-6-3)+4(x-3). 15-X+2+4x-12. 3x + 5 ... Objective 2: To find the slope when given an equation of a line.
Step-by-step explanation:
<span>the hypotenuse (cos = adj/hyp).
</span><span>the hypotenuse (sin = opp/hyp).
</span><span>the hypotenuse (tan = opp/adj).
</span>
hope this helps........