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3 years ago

The length of a rectangle is (3x - 5) inches, and its width is 2x inches. Find the area of the rectangle.

Mathematics

2 answers:

n200080 [17]3 years ago

8 0

Answer:

6x^2 - 10x inches ^2

Step-by-step explanation:

The area of a rectangle is

A = l*w

= (3x-5) * (2x)

= 6x^2 - 10x

SVETLANKA909090 [29]3 years ago

7 0

Answer:

The area of the rectangle is 6x^2(squared)-10x

Step-by-step explanation:

To find the area of rectangles, you must multiply the length by the width. The formst for this is A=LxW. When you substitute each part of the equation in, it becomes 2x(3x-5). When you have parentheses, distribute the number on the outside to each number(or variable) on the inside. First, multiply 2x by 3x. This leaves you with 6x^2(squared). Then, multiply the 2x by the -5. This leaves you with -10x. Combine each part to get 6x^2(squared)-10x. :)

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To find:

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Solution:

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Solve the following triangle in which given sides are a=7 b=7 c=9

blagie [28]

We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º

Answer:
a=7; A=50º
b=7; B=50º
c=9; C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

a=7; A=50º
b=7; B=50º
c=9; C=80º

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Fofino [41]

Option 2: $\frac{4x-3y}{3x+4y}$ is the right answer

Step-by-step explanation:

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To solve the fraction, Taking LCM in denominator and numerator

$=\frac{\frac{4x-3y}{12} }{\frac{3x+4y}{12}}$

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Hence,

Option 2: $\frac{4x-3y}{3x+4y}$ is the right answer

Keywords: fractions, simplification

Learn more about fractions at:

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