Answer:
y=895•1.07^x Y is the population of quails and X is the amount of years that have passed.
Step-by-step explanation:
hope this helps
B. 0
G(6)= 6 - 8 = -2
F(-2) = 6(-2) + 12 = 0
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
4/15, 5/9 and 3/5.
Hope this helps! :)
Answer:
fshscssjjsv 57
Step-by-step explanation:
fsuevwuwhw 58
