The answer is (6•n) - (6•3)= 6n-9
Answer:
n = -7
Step-by-step explanation:
Solve for n:
-3 n - 5 = 16
Hint: | Isolate terms with n to the left-hand side.
Add 5 to both sides:
(5 - 5) - 3 n = 5 + 16
Hint: | Look for the difference of two identical terms.
5 - 5 = 0:
-3 n = 16 + 5
Hint: | Evaluate 16 + 5.
16 + 5 = 21:
-3 n = 21
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of -3 n = 21 by -3:
(-3 n)/(-3) = 21/(-3)
Hint: | Any nonzero number divided by itself is one.
(-3)/(-3) = 1:
n = 21/(-3)
Hint: | Reduce 21/(-3) to lowest terms. Start by finding the GCD of 21 and -3.
The gcd of 21 and -3 is 3, so 21/(-3) = (3×7)/(3 (-1)) = 3/3×7/(-1) = 7/(-1):
n = 7/(-1)
Hint: | Simplify the sign of 7/(-1).
Multiply numerator and denominator of 7/(-1) by -1:
Answer: n = -7
Answer:
The quotient of two integers may not always be an integer.
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
Step-by-step explanation:
The student is not largely correct!
The sum, difference, and product of two integers is indeed always an integer.
But, the quotient of two integers may not always be an integer.
- For example, the quotient of integers 4 and 2 will be an integer.
i.e.
4/2 = 2
- But, if we take the quotient of 2 and 3, the result will not be an integer.
i.e.
2/3 = 0.67
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
Answer:
-4<-1 and -1<4
Step-by-step explanation:
The speed upstream is the difference between the boat speed and the current speed. It is (12 mi)/(4 h) = 3 mph.
The speed downstream is the sum of the boat speed and the current speed. It is (32 mph)/(4 h) = 8 mph.
The speed of the boat is the average of these: (3 + 8)/2 = 5.5 mph.
The speed of the current is that less the difference: 5.5 - 3 = 2.5 mph.
_____
<u>Check</u>
Boat + Current = 5.5 + 2.5 = 8 mph
Boat - Current = 5.5 - 2.5 = 3 mph
