The answer is 3,750. you would multiply 1250 by 3
Answer:
The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i
Step-by-step explanation:
1) This claim is mistaken.
2) The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

For example:
3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

We'll have <em>n </em>different complex roots, not necessarily 2i.
For example:
Taking 3 polynomial equations with real coefficients, with


2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

5x + 9 over 2
Explanation:
I know I’m right, but I hope this helped. Have a great day
Answer:
2 - 2y^2 - x/y
Step-by-step explanation:
2x^2/x^2 = 2
and
x^2/xy = x/y
therefore
2x^2/x^2 - y^2 - x^2/xy - y^2
= 2 - y^2 - x/y - y^2
= 2 - y^2 - y^2 - x/y
= 2 - 2y^2 - x/y
Answer:
check my explanation
Step-by-step explanation:
yes it is c.
by adding the ones on screen
it is option C