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vovangra [49]
3 years ago
8

N/8 = (-7) help please

Mathematics
2 answers:
sdas [7]3 years ago
6 0

Answer:

n = -56

Step-by-step explanation:

n/8 = (-7)

Multiply each side by 8

n/8* 8 = (-7)*8

n = -56

topjm [15]3 years ago
3 0

Answer:

n=-56

Step-by-step explanation:

We can use algebra and simplify the equation until we have n isolated.

\frac{n}{8} = -7\\\frac{n}{8}\cdot8 = -7\cdot8\\\\n=-56

Hope this helped!

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Please helppp it’s confusing!!!
Valentin [98]

Answer:

First you'd look at PEMDAS (parenthesis, exponent, multiplication, division, addition, and subtraction( you'd look at them in this order to solve the equation properly.))

So there is a parenthesis, that would be the 3(2^0). ignore the three, because you're focusing on the parenthesis. Any number other than zero with an exponent of zero will always be one. leaving you with 3(1).

So by now you should know (depending on your level of mathematics, That a number beside a single number in a parenthesis is multiplication. so 3 times 1.

Knowing that any number, other than zero, multiplied by 1 is the number itself, The answer is 3

In short,  3(2^0) = 3

7 0
3 years ago
What is 21 rounded to the nearest ten?
BARSIC [14]

Answer:

20

Step-by-step explanation:

the two closest are 20 and 30

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4 0
3 years ago
When 2 fractions have different denominators
hammer [34]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Does anyone know the answer to this!?
PolarNik [594]

Answer:

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},

where

|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

So,

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

4 0
3 years ago
Show that the bowtie method can be used to multiply (2x -27)(-x +15)
Nikolay [14]

( 2x − 27 ) ( −x + 15 )

= ( 2x + −27 ) ( −x + 15 )

= ( 2x ) ( −x ) + ( 2x ) ( 15 ) + ( −27 ) ( −x ) + ( −27 ) ( 15 )

= −2x^2 + 30x + 27x − 405

= −2x^2 + 57x − 405

4 0
3 years ago
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