Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
-12°C
Step-by-step explanation:
6AM = 2°C
8AM= -2°C
10AM= -6°C
12AM= -8°C
2PM= -12°C
Answer:
Her first mistake was in Step 2. She added 0.2 to each term instead of multiplying by 0.2.
Step-by-step explanation:
CORRECT WAY:
0.2(4+1.4y - 2.1)
0.8 + 0.28y - 0.42
0.8 - 0.42 + 0.28y
0.38 + 0.28y
WHAT TAMARA DID:
0.2(4+1.4y - 2.1)
How she got 4.2: 0.2 + 4 = 4.2
How she got 1.6y: 0.2 + 1.4y = 1.6y
How she got -1.9: 0.2 + -2.1 = -1.9
WHAT SHE DID HERE IS WRONG. REMEMBER WHEN IT IS __( ______) IT MEANS THAT YOU NEED TO MULTIPLE NUMBER OUTSIDE THE PARATNESS TO EVERY NUMBER THAT IS INSIDE THE PARATNESS.
Answer:
About 8.6 units.
If you count up and sideways, it would be 12, but then there is some stuff we need to calculate at the end because it's not fully.
