John can reach 60 centimeters above the top of his head. If John is 2 meters tall, how high can he reach?

Plisss help me on my assesment

rosijanka [135]

Answer:

coefficient variables

15. xy

3. x

4. a

5 0

3 years ago

The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

sertanlavr [38]

Answer:

20/3 ft or 6 2/3 ft

Step-by-step explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W

$L = \dfrac{A}{W}$

$L = \dfrac{56~\frac{2}{3}~sq~ft}{8~\frac{1}{2}~ft}$

Change the mixed numbers into fractions.

$a\frac{b}{c} = \dfrac{ac + b}{c}$

$L = \dfrac{\frac{56 \times 3 + 2}{3}}{\frac{8 \times 2 + 1}{2}}$

$L = \dfrac{\frac{170}{3}}{\frac{17}{2}}$

$L = \dfrac{170}{3} \div \dfrac{17}{2}$

$L = \dfrac{170}{3} \times \dfrac{2}{17}$

$L = \dfrac{170 \times 2}{3 \times 17}$

$L = \dfrac{17 \times 10 \times 2}{3 \times 17}$

$L = \dfrac{10 \times 2}{3}$

$L = \dfrac{20}{3}$

Answer: 20/3 ft or 6 2/3 ft

4 0

4 years ago

4(x+1.5)=38 solve for x

Kitty [74]

Answer:

x = 8

Step-by-step explanation:

4(x+1.5)=38

Distribute the 4

4x +6 = 38

Subtract 6 from each side

4x+6-6 = 38-6

4x = 32

Divide each side by 4

4x/4 = 32/4

x = 8

3 0

4 years ago

Solve -0.5y > 15. Check your solution.

Sedbober [7]

The following answer is:

y<<span>−<span>30

Hope this helps!</span></span>

3 0

4 years ago

Read 2 more answers

Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre

choli [55]

Answer:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

$\hat p=\frac{46}{115}=0.4$ estimated proportion of people that have traded in their old car

$p_o=0.48$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

4 0

4 years ago