The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.
m∠4=m∠1+m∠2m∠4=m∠1+m∠2
Proof:
Given: ΔPQRΔPQR
To Prove: m∠4=m∠1+m∠2m∠4=m∠1+m∠2
StatementReason1ΔPQRΔPQR is a triangleGiven2m∠1+m∠2+m∠3=180°m∠1+m∠2+m∠3=180°Triangle Sum Theorem3∠3∠3 and ∠4∠4 form a linear pairDefinition of linear pair.4∠3∠3 and ∠4∠4 are supplementaryIf two angles form a linear pair, they are supplementary.5m∠3+m∠4=180°m∠3+m∠4=180°Definition of supplementary angles.6m∠3+m∠4=m∠1+m∠2+m∠3m∠3+m∠4=m∠1+m∠2+m∠3Statements 2, 5 and Substitution Property.7m∠4=m∠1+m∠2m∠4=m∠1+m∠2Subtraction Property. im 99.9 perecent sure this is right bc im only in middle school but hope it helps
Answer:
Yeah, I got it, y'all keep postin' this, Lol
Step-by-step explanation:
Thx yous
4 thousands and 4 hundreds. This is the answer.
Answer:
Here's what i know:
x + y = 23
3y / 20 =x
Here we can use substitution to help find our answer:
y + 3y/20 = 23
20y/20 + 3y/20 = 23
23y/20 = 23
23y = 23 * 20
y = 23 * 20 / 23
y = 20
x + 20 = 23
x = 3
