Answer:
<u>For the system of equations given, x = 0</u>
Step-by-step explanation:
<u>1. Let's solve the system of equations to find out the value of x:</u>
1st equation:
x+ 2y = 6
x = 6 - 2y (Subtracting 2y at both sides)
2nd equation:
6y = x + 18
Replacing x with the result of the 1st equation:
6y = (6 - 2y) + 18
6y = 6 - 2y + 18
6y + 2y = 18 + 6 (Adding 2y at both sides)
8y = 24
<u>y = 24/8 = 3</u> (Dividing by 8 at both sides)
Now we can find out the value of x:
x + 2y = 6
x + 2 * 3 = 6
x = 6 - 6 (Subtracting 6 at both sides)
<u>x = 0</u>
3. Let's prove that x = 0 and y = 3 in the 2nd equation:
6y = x + 18
6 * 3 = 0 + 18
<u>18 = 18</u>
<u>We proved that x = 0 and y = 3 are correct.</u>