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diamong [38]
3 years ago
9

A gym memebership costs a flat fee of $68 and an additional $19.99 per month.Since she became a member Ellen has paid the gym $2

07.93 how many months has Ellen been a member of the gym
Mathematics
1 answer:
fomenos3 years ago
3 0

Answer:

She has been a member of the gym for seven months

Step-by-step explanation:

In this question, we are asked to calculate the number of months a customer has been a member of a gym, given the pricing template of the gym.

Now, as we can see from the question, there are two kinds of fees to be paid. The flat fee and the subscript class.

First, let’s represent the number of months she has been a member of the gym by m. This means the total amount of money she has paid for m months would be m * 19.99m

Now, recall, we have a flat fee of $68, adding this to the total monthly payment for m months bring the wages to 19.99m + 68

This is said to equal $207.93

This means;

19.99m + 68 = 207.93

19.99m = 207.93 -68

19.99m = 139.93

m = 139.93/19.99 = 7

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A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
Name 4 real life situation in which integers can be used <br>​
ArbitrLikvidat [17]

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Step-by-step explanation:

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3 years ago
What is the value of -2(x+5) Please I'm in need of help
irina [24]

Answer:

-2x - 10

Step-by-step explanation:

-2 x X = -2x

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Put them together to get:

-2x - 10

5 0
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11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

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Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

4. a=2, b=2

c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}

5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

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If a spring stretches 10.4 with 80 pounds attached how far will it stretch with 70 pounds attached?
sattari [20]

Answer:

10.4 * 70/80 = 9.1


7 0
3 years ago
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