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VladimirAG [237]
3 years ago
9

Please answer it is related to square root​

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

Step-by-step explanation:

2\sqrt{8}+3\sqrt{50}=2\sqrt{2*2*2} + 3\sqrt{5*5*2}\\\\= 2*2\sqrt{2}+3*5\sqrt{2}\\\\=4\sqrt{2}+15\sqrt{2}\\\\= 19\sqrt{2}

3\sqrt{12}+4\sqrt{27}=3\sqrt{2*2*3}+4\sqrt{3*3*3}\\\\=3*2\sqrt{3}+4*3\sqrt{3}\\\\=6\sqrt{3}+12\sqrt{3}\\\\=(6+12)\sqrt{3}\\\\= 18\sqrt{3}

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How do I find the period of y = -2 cos 0.5x
nevsk [136]
Use the form (bx-c)+ d to find the amplitude , period shift, phase, and vertical shift.
amplitude:2 
period:12.56637061
phase shift : 0(0to the right ) 
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4 0
4 years ago
If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13
Lelu [443]

Answer:

0.02 or 2% = Beta

Step-by-step explanation:

Given that,

Risk-free rate = 7 percent

Expected return on the market = 10 percent

Expected return on Security J = 13 percent

Therefore, the beta of Security J is calculated as follows;

Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

13 percent = 7 percent + Beta (10 percent - 7 percent)

0.13 - 0.07 = 0.03 Beta

0.06 = 0.03 Beta

0.06 ÷ 0.03 = Beta

0.02 or 2% = Beta

6 0
3 years ago
Help!!!!!!!!!!!!!!! need this done by tomorrow night
RUDIKE [14]
....................................................................
4 0
3 years ago
Yo i need help please no links i just need the correct answer to pass this
Black_prince [1.1K]
3.2 i believe!!! sorry if i’m late
6 0
3 years ago
I need help with this question ( see image). Please show workings.​
Ksju [112]

Answer:

Percentage of the garden that is used to make the pond = 53.8%

Step-by-step explanation:

Area of a garden = 104 m^2

Area of a garden = 104 m^2Area of a pond = 56 m^2

Percentage of the garden that is used to make the pond

= (56/104) × 100%

= 53.8%

Hope this Helps!!!

5 0
3 years ago
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