fir the x missing think is 11 and for the other f(×) is 24
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
Answer:
B.) f(x) = 3(4)x − 1
Step-by-step explanation:
A) f(x) = 12(4)x
B.) f(x) = 3(4)x − 1
C.) f(x) = 4(12)x
D.) f(x) = 4(3)x − 1
Given:
f(x+1) = 4f(x)
f(2)=12
f(2) = 12
f(3) = 4f(2) = 4 * 12 = 48
f(3)=48 and f(2)=12
From f(3)=48 and f(2)=12
r=48/12
=4
r=common ratio
Recall,
f(2)=12=ar
r=4
f(2)=ar=12
a*4=12
a=12/4
a=3
an=ar^(n-1)
For x term
an=3*4(x-1)
B.) f(x) = 3(4)x − 1
I think the answer is 216 because their are 12 months in a year and 12 times 18 is 216.
Answer:
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