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9966 [12]
3 years ago
9

Solving Systems by Elimination

Mathematics
1 answer:
Karolina [17]3 years ago
8 0

Answer:

x=-2, y=-3. (-2, -3).

Step-by-step explanation:

-5x+4y=-2

2x-7y=17

-------------------

2(-5x+4y)=2(-2)

5(2x-7y)=5(17)

---------------------

-10x+8y=-4

10x-35y=85

-------------------

-27y=81

y=81/-27

y=-3

2x-7(-3)=17

2x+21=17

2x=17-21

2x=-4

x=-4/2

x=-2

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lilavasa [31]

Answer:

f(2) = 9

Step-by-step explanation:

It's give in the question,

Two different functions are,

f(x) = 4x + 1

g(x) = -2x

Then we have to find the output value of function 'f' for the input value x = 2.

By substituting the value of x in the function 'f',

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3 years ago
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DENIUS [597]

2(\frac{2}{5}x + 4) =  \frac{4}{5}x + 4 which is the second option is the equivalent expression.

Explanation:

First,  we need to calculate the value of two-fifths of x. It means 2 portions out of the five portions of x which equates to \frac{2}{5}x.

Now we calculate the values of the two expresssions on the LHS.

1) 2 (two-fifths x + 2) = 2 (\frac{2}{5}x + 2) = \frac{4}{5}x + 4.

2)  (two-fifths x + 4) = 2(\frac{2}{5}x + 4) =  \frac{4}{5}x + 8.

Now we determine values of the four expressions on the RHS.

1) Two and two-fifths x + 1 = 2\frac{2}{5}x + 1

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Out of the various LHS and RHS values, the 1^{st} LHS value and 2^{nd} RHS value is the same. So option 2 is the answer.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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