If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.
the sqrt525^7 = 3359983566.19
So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.
(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)
Left down, or “Starting at the origin, go 4 spaces to the right and then 1and1/2 spaces up.” This would bring you to the point (4,1and1/2)
S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50
2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's
R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's
S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's
Answer:
n+12 <4
Step-by-step explanation:
<span>The theorems in this lesson relate to all of the following (tangents, arcs, and chords) except for <u>radii.</u></span>
