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3 years ago

90:(3+6)-20.(60-55) propiedad

Mathematics

1 answer:

Roman55 [17]3 years ago

7 0

Answer:

https://www.commoncoresheets.com/Math/Properties/Applying%20Properties%20of%20Operations/Spanish/2.pdf

Step-by-step explanation:

This will help you:) not a spam link its a pdf that brings you straight to the worksheet <3

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The 100th term in 8, 13, 18,23, 28,...

Lunna [17]

Answer:

The 100th term of the sequence is 503.

Step-by-step explanation:

Given : Sequence 8, 13, 18,23, 28,...

To find : The 100th term in the sequence ?

Solution :

Sequence 8, 13, 18,23, 28,... is the arithmetic sequence

Where, First term is a=8

The common difference is d=13-8=5

The nth term of the sequence is given by $a_n=a+(n-1)d$

The 100th term is given by,

$a_{100}=8+(100-1)5$

$a_{100}=8+(99)5$

$a_{100}=8+495$

$a_{100}=503$

The 100th term of the sequence is 503.

3 0

3 years ago

Jack earns $50 for washing cars on the weekend. he makes an average of $4.25 in tips per hour. write the function of joe's earni

solong [7]

Add up how much gets paid and how many hours he work I hope this helps good luck !!!!!!!!!!!!!!!

8 0

3 years ago

Sari sold 300 boxes of greeting cards in November. In december she sold 500. What was the percentage increase in her sales

grigory [225]

There was a 66 $\frac{2}{3}$ % increase from Sari's sales from November to December.

To find the percentage increase in her sales, we must first find the amount her sales increased. We can do that by subtracting the greeting cards sold in November from the number of greeting cards sold in December. Substituting values and simplifying, we get that she sold 200 more greeting cards in December.

To find what percent increase this is, we must find what percent 200 is of the number of greeting cards sold in November. We can do this by dividing 200 by the number of cards sold in November (300), and then multiplying by 100 (to make it a percent). Doing this, we get $\frac{2}{3}$ * 100 which gives us our answer of 66 $\frac{2}{3}$ %.

3 0

3 years ago

Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME

Bess [88]

Answer:

58°

Step-by-step explanation:

If m AM=125°, then m∠AOM=125°.

If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).

Thus,

m∠FOA=360°-150°-125°=85°.

If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).

Hence,

m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.

Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus

m∠AME=1/2m∠EOA=58°.

7 0

3 years ago

Plz hwlp fast i need help like rn

frozen [14]

I don't know so here's a meme, lol take a joke, it's 12am, I'm exhausted, and delaireus, and I need points.

3 0

3 years ago