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marysya [2.9K]
2 years ago
11

Solve for a 3(2a+6)=4(a+10

Mathematics
1 answer:
Svetllana [295]2 years ago
7 0

Answer:

a = 11

Step-by-step explanation:

distribute and combine like terms

6a + 18 = 4a + 40

2a = 22

a =11

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Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista
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Answer:

  A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

  a^2 = (12-6)^2 +3^2 = 45

  a = √45 = 3√5

and

  b^2 = (6 -2)^2 +4^2 = 32

  b = √32 = 4√2

Then the total length, in grid squares, is ...

  3√5 + 4√2 = 6.7082 +5.6569 = 12.3651

If each grid square is 1/4 mile, then 12.3651 grid squares is about ...

  (12.3651 squares) · (1/4 mile/square) = 3.0913 miles

The proposed route is too long by 0.09 miles.

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3 years ago
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2x(x-1) has the least common denominator
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2 years ago
2.38+4.89=3+ _ <br><br>changing expressions??
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Add 2.38 and 4.89 then subtract 3 giving you 4.27
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3 years ago
For the following hypothesis test, H0: μ ≥ 150Ha: μ &lt; 150​the test statistic a. must be positive. b. must be negative. c. can
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Answer:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

And since we are conducting a lower unilateral lest  then we expected that the value for the statistic would be negative. And the correct answer would be:

b. must be negative

Step-by-step explanation:

Data given and notation      

\bar X represent the sample mean    

s represent the standard deviation for the sample      

n sample size      

\mu_o =150 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is lower than 150, the system of hypothesis would be:      

Null hypothesis:\mu \geq 150      

Alternative hypothesis:\mu < 150      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

And since we are conducting a lower unilateral lest  then we expected that the value for the statistic would be negative. And the correct answer would be:

b. must be negative

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3 years ago
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If you multiply 1/3 x 9 = 3
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