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lozanna [386]
3 years ago
11

Survey data involving two random samples of students at law school are shown. The surveys were taken comparing the age of studen

ts in 1900 to the age of students in 2014
Whats the answer

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:

A and C if you don't believe me look at this link down below

Step-by-step explanation:

https://fsassessments.org/assets/documents/answer-keys-paper/FSA_2018_7M_Practice-Test_Answer-Key_PBT_Final.pdf

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The local home improvement store wants to increase their inventory. Last year 40 lawn mowers cost them $4,776.
hoa [83]
40 mowers = $4,776

Multiply the above equation by 3
120 mowers = $14,328
7 0
3 years ago
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Multiply. Just multiply the decimals. Please?
Alex17521 [72]

1) 0.009

2) 0.294

3) 0.0612

4) 33.62

5) 26.46

6) 1.824

5 0
3 years ago
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If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?
fgiga [73]
X in the first equation

because 3x + 6y = 9 can be reduced by dividing by 3, thus, giving u 
x + 2y = 3.....x = -2y + 3...which u would sub in for x in the other equation
7 0
3 years ago
WILL AWARD BRAINLIEST
stepan [7]

Answer:

1. a. 3xy²(7x²y³ + 5x - 4y)

2. a. (3x + 2)(5x + y)

3. d. (2a + b)(5x - 4)

Step-by-step explanation:

For #1, your answer was missing an exponent, which I boldfaced. Every term has a <em>y</em><em>²</em><em> </em>in common. Then, in numbers 2 and 3, just factor each group one at a time.

Ex: [10ax + 5bx] - [8ay - 4by]

4 0
3 years ago
Insulin is used to regulate sugar in the bloodstream. A dose of 10 units breaks down by about 5% each minute after injection. Ho
s344n2d4d5 [400]

Answer:

Explanation:

• The initial dose of the Insulin = 10 Units

The insulin breaks down by about 5% each minute, therefore:

• The decay rate, r= 5%

We want to determine the time it will take for the remaining dosage to be half (5 units) of the original dose.

We use the exponential decay function:

N(t)=N_o(1-r)^t

Substituting the given values, we have:

\begin{gathered} 5=10(1-0.05)^t \\ \frac{5}{10}=0.95^t \\ 0.5=0.95^t \end{gathered}

To solve for t, we change to logarithm form.

8 0
1 year ago
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