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Stella [2.4K]
3 years ago
6

Exercise 2.14.4: Geometry 2.0

Computers and Technology
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

Explanation:

One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.

Fill a rectangular baking glass dish with water.

Place a plastic bag with ice in the water near the left edge of the dish.

Place a lighted lamp near the left edge of the dish so that its light falls directly on the plastic bag.

Put a few drops of ink in the water.

The student did not observe any circulation of ink in the water as expected because the experiment had a flaw. Which of these statements best describes the flaw in the experiment? (2 points)

Not enough ink was added.

Not enough water was taken.

The dish was too small for the experiment.

The lamp and the ice bag were at the same place.

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Luda [366]

Answer:

The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

   if num[i].isdigit():

       if(int(num[i])>= 0 and int(num[i])<8):

           BCDValue += BCD[i]+" "

       else:

           valid = False

           break;

   else:

       valid = False

       break;

if(valid):

   print(BCDValue)

else:

   print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value)  to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

   if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

       if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

           BCDValue += BCD[i]+" "

       else:

If otherwise, then the input string is invalid and the loop is exited

<em>            valid = False</em>

<em>            break;</em>

If otherwise, then the input string is invalid and the loop is exited

<em>    else:</em>

<em>        valid = False</em>

<em>        break;</em>

If valid is True, then the BCD value is printed

<em>if(valid):</em>

<em>    print(BCDValue)</em>

If otherwise, it prints Invalid

<em>else:</em>

<em>    print("Invalid")</em>

7 0
3 years ago
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