ok Step-by-step explanation:
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
We have the function:
()=−2(−3)^4+1
We need to go from this equation to the parent function x^4. To do that, we first do a vertical translation of 1 unit below. That is:
Vertical translation: f(x) - 1
= −2(−3)^4
Now, we make a horizontal shift of 3 units to the left, replacing x by x + 3:
f(x + 3) + 1 = −2()^4
Horizontal shift: f(x + 3) - 1
= −2x^4
We can make a horizontal expansion if we multiply this function by 1/2:
Horizontal expansion: ( f(x + 3) - 1 ) / 2
= -x^4
Finally, we make a reflection around the x-axis by multiplying this result by -1:
x-axis reflection: -( f(x + 3) - 1 ) / 2
= x^4
Answer:
Yes
Step-by-step explanation:
If you divide all the sides of the larger triangle by 3, it's equivalent to the sides of the smaller triangle. Therefore, they are similar.