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2 years ago

I need help PLEASE !!!! Write a cosine function that has an amplitude of 2, a midline of 4 and a period of 4.

Mathematics

1 answer:

stiv31 [10]2 years ago

5 0

Answer:

$\mathbf{y = 2cos ( \dfrac{\pi}{2}(x - 0) + 4}$

Step-by-step explanation:

The standardized cosine function is ;

$\mathbf{y = Acos (Bx + C) +D}$

Amplitude |A| = 2

Period $\dfrac{2 \pi}{B }= 4$

2π = 4B

$B = \dfrac{2 \pi}{4}$

$B = \dfrac{\pi}{2}$

Midline y = 4; D = 4

Phase shift; since no phase shift is given; then C = 0

The cosine function: $\mathbf{y = 2cos ( \dfrac{\pi}{2}(x - 0) + 4}$

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Find the quotient. 514÷15 A. 720 B. 7834 C. 267 D. 314

Law Incorporation [45]

Answer:314

Step-by-step explanation:

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3 years ago

The volume of the cell phone is 75 cubic centimeters. Write and solve an equation to find the height of the cell phone. Round yo

prohojiy [21]

Answer:

Equation: $Height = \frac{75}{Area}$

Step-by-step explanation:

The question is incomplete as the dimension of the phone was not given.

However, the following explanation will guide you

Given

$Volume = 75\ in^3$

Required

Determine the Height

Volume is calculated as thus;

$Volume = Area * Height$

Substitute 75 for Volume

$75= Area * Height$

Divide through by Area

$Height = \frac{75}{Area}$

The above represent the equation to solve for Height

To solve for height, we need the dimension of the phone or the area.

Take for instance; the length and width of the phone is 5 by 5 inches;

The height would be:

$Height = \frac{75}{5 * 5}$

$Height = \frac{75}{25}$

$Height = 3\ inches$

5 0

3 years ago

Write an inequality with a solution of x < -7 that you solve in 2 or more steps.

Ainat [17]

Example: 2x + 6 < -8

There's 2 steps to solve this one.
2x + 6 < -8
Subtract 6 from both sides
2x < -14
Divide both sides by 2
x< -7

4 0

3 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$