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guajiro [1.7K]
2 years ago
12

I need help PLEASE !!!! Write a cosine function that has an amplitude of 2, a midline of 4 and a period of 4.

Mathematics
1 answer:
stiv31 [10]2 years ago
5 0

Answer:

\mathbf{y = 2cos ( \dfrac{\pi}{2}(x - 0) + 4}

Step-by-step explanation:

The standardized cosine function is ;

\mathbf{y = Acos (Bx + C) +D}

Amplitude |A| = 2

Period \dfrac{2 \pi}{B }= 4

2π = 4B

B = \dfrac{2 \pi}{4}

B = \dfrac{\pi}{2}

Midline y = 4;  D = 4

Phase shift; since no phase shift is given; then C = 0

The cosine function: \mathbf{y = 2cos ( \dfrac{\pi}{2}(x - 0) + 4}

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The fraction is \frac{5}{8}

Step-by-step explanation:

Let,

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\frac{x-3+1}{x}=\frac{3}{4}\\\\\frac{x-2}{x}=\frac{3}{4}

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Keywords: fraction, division

Learn more about fractions at:

  • brainly.com/question/11549940
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3 years ago
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