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3 years ago

Which ratio can be used to form a proportion with the given ratio?

2 answers:

7 0

7 / 12 = 0.583333333

Divide them all to see which one equals 0.583333333.

A.

8 / 13 = 0.615384615

B.

10 / 15 = 0.666666667

C.

14 / 19 = 0.736842105

D.

21 / 36 = 0.583333333

Therefore, your answer is D.

ankoles [38]3 years ago

3 0

D.
<span>If you multiply both numbers in the given proportion by 3, you get answer D:
7 x 3 = 21
12 x 3 = 36.
Because you can multiply both of the numbers in the given ratio by the same number (3) to get the ratio in answer D, they are a proportion.</span>

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What are two things you will need to write an equation for a line?

vlabodo [156]

Answer:

Slope and y intercept.

Step-by-step explanation:

This is necassary to write the equation of a line in y=mx+b

m is where the slope goes, and b is the y intercept.

Alternatively, you could also write the equation for a line with a point on the line and the slope.

You would then write it in point slope formula:

y-y1=m(x-x1)

This can later be converted into slope intercept form.

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3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

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2 years ago

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Alexeev081 [22]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 4 is in this form

with y- intercept c = 4 → A

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B’(9,6)

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2 years ago

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