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lesantik [10]
2 years ago
14

A bag holds 13 marbles. 6 are blue, 2 are green, and 5 are red. If you select two marbles from the bag in a row without replacin

g the first marble, what is the probability that the first marble is blue and the second marble is green? Note: you are not replacing any marbles after each selection. YOU MUST SHOW ALL OF YOUR WORK FOR FULL CREDIT. SHOW THE INDIVIDUAL PROBABILITIES FIRST AND THEN THE FINAL ANSWER. please help me
Mathematics
1 answer:
lutik1710 [3]2 years ago
6 0

The probability of first drawing a blue one, and then a green one, is:

P = 0.19

<h3>How to get the probability?</h3>

There is a total of 13 marbles, such that:

  • 6 are blue.
  • 2 are green.
  • 5 are red.

Now we draw two marbles, we want to get the probability that the first one is blue, this is equal to the quotient between the number of blue balls and the total number of balls.

p₁ = 6/13

Now, after that, we want to draw a green one. The probability is computed in the same way (notice that now there are 12 marbles).

p₂ = 5/12

Finally, the joint probability is the product of these two:

P = (6/13)*(5/12) = 0.19

If you want to learn more about probability, you can read:

brainly.com/question/251701

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7 0
3 years ago
Determine the constant of variation for the direct variation given.
ohaa [14]

Answer:

B. 5

Step-by-step explanation:

We have been given that R varies directly with S. When S is 16, R is 80. We are asked to find constant of variation.

We know that two directly proportional quantities are in form y=kx, where,

k = Constant of variation.

Upon substituting our given values, we will get:

R=k*S

80=k*16

\frac{80}{16}=\frac{k*16}{16}

5=k

Therefore, the constant of variation is 5 and option B is the correct choice.

6 0
3 years ago
what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction
mote1985 [20]
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5)  let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

s(5)=12.5(1-(1/5)^5)

s(5)=12.496

as an improper fraction:

(125/10)(3124/3125)

390500/31240

1775/142
6 0
3 years ago
Please help! 20 pts.
Daniel [21]
Your answer would be the last option, 80 cm.

As this is a right triangle, you can use Pythagoras's Theorem, a² + b² = c², where 'c' is the hypotenuse and 'a' and 'b' are the legs, to find the missing side.

This gives us:

48² + 64² = 2,304 + 4,096 = 6,400
√6,400 = 80

So 80 is your answer.

I hope this helps!
5 0
3 years ago
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How would you round the number 32 to the nearest 100
saw5 [17]

Answer:

Remember, we did not necessarily round up or down, but to the hundred that is nearest to 32. When rounding to the nearest hundred, like we did with 32 above, we use the following rules: A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.

Step-by-step explanation:

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3 years ago
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