Question

A bag holds 13 marbles. 6 are blue, 2 are green, and 5 are red. If you select two marbles from the bag in a row without replacing the first marble, what is the probability that the first marble is blue and the second marble is green? Note: you are not replacing any marbles after each selection. YOU MUST SHOW ALL OF YOUR WORK FOR FULL CREDIT. SHOW THE INDIVIDUAL PROBABILITIES FIRST AND THEN THE FINAL ANSWER. please help me

Answer 1

The probability of first drawing a blue one, and then a green one, is:

P = 0.19

How to get the probability?

There is a total of 13 marbles, such that:

• 6 are blue.
• 2 are green.
• 5 are red.

Now we draw two marbles, we want to get the probability that the first one is blue, this is equal to the quotient between the number of blue balls and the total number of balls.

p₁ = 6/13

Now, after that, we want to draw a green one. The probability is computed in the same way (notice that now there are 12 marbles).

p₂ = 5/12

Finally, the joint probability is the product of these two:

P = (6/13)*(5/12) = 0.19

If you want to learn more about probability, you can read:

brainly.com/question/251701