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VLD [36.1K]
3 years ago
11

PLEASE HELP ME NOW!!!!!!!

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:

Step-by-step ex$ in 6 in 14 dt lenght times width times hight planation:

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There were 60 ducks living in a pond. If the number living at the pond increased by 30%, how many ducks now live at the pond?
timama [110]

Answer:

78

Step-by-step explanation:

You take the original total: 60, and multiply it by 30 to get 1,800. You then divide 1,800 by 100 to get 18. 18 is your 30%. Now, you add the 30% to 60 getting your total number of ducks: 78.

The equation version:

\frac{a}{60} = \frac{30}{100}

It is just proportions.

3 0
3 years ago
Heather paid $1,493.30 for a computer. If the price paid includes a 9% sales tax, which of the following equations can be used t
aliina [53]
A because x is the original price, so you multiply by the tax (9%) which would convert to 1.09 which you would multiply to the x

3 0
3 years ago
Solve please lol :) but like fr I need help
11111nata11111 [884]

Answer:

2 1/4

Step-by-step explanation:

1/3 divided by 1/6 is 2

3/4 plus 2 is 2 3/4

2 3/4 minus 6/12 is simplified to 2 9/12 minus 6/12, which is 2 3/12

2 3/12 is simplified to 2 1/4

7 0
3 years ago
Read 2 more answers
3 cm 10 cm 10 cm 3cm ​
erik [133]

Answer:

what is the question about the given numbers

8 0
3 years ago
Read 2 more answers
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
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