Answer:
Check the ecplanation
Step-by-step explanation:
A set of three vectors in
represents a matrix of 3 column vectors, and each vector containing 4 entries (that is, a matrix of 4 rows, and 3 columns).
Let A be that 4x 3 matrix. The columns of A span
. if and only if A has a pivot position in each row. So, there are at most 3 pivot positions in the matrix A, but the number of rows is 4, therefore, there exist at least one row not having a pivot position. If A does not have a pivot position in at least one row, then the columns of A do not span
. It implies that the set of 3 vectors of A does not span all of
.
In general, the set of n vectors in
represents a matrix of in rows, and n columns (an in x matrix). So, there are at most n pivot positions in the matrix A, but n is less than the number of rows. In therefore, there exist at least one row that does not contain a pivot position.
And, hence the set of n vectors of A does not span all of
. for n < m
Answer:
5.625
Step-by-step explanation:
Answer:
5 left, (5,_) and 12 up. (5,12)
Step-by-step explanation:
Answer:
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Step-by-step explanation:
Vertical lines never have a defined slope as you can never divide a number by zero
I believe 4(x - 3)=32 could help I haven’t done an equation from the unit in months so hopefully that looks familiar to you.