Question

I need help with this:

Answer 1

Answer: 75 meters

Step-by-step explanation:

Given: The variable ll models the anchor's elevation (in meters) relative to the water's surface t seconds after the ship drops its anchor as

$I=-2.4t+75$

To find the initial height, substitute t=0 in the equation, we get

$\Rightarrow\ I=-2.4(0)+75$

$\Rightarrow\ I=75$

Therefore, the initial height of the anchor = 75 meters .

Answer 2

Answer:

The answer is 75 meters.

Step-by-step explanation:

I= -2.4t + 75

I= -2.4(0) + 75

I= 0 + 75

I= 75 meters

I did it on Khan and it was correct.