Answer:
4. $648
5. $86.40
Step-by-step explanation:
You take the percent (we'll take 4 for example, so 8%) and change it to a decimal: .08. You then multiply the decimal (.08) by your other number (in this case $600) and the resulting number is your answer, but not final. Take whatever the answer was (in this case 48) and add it to the orignal number (600) to get $648.
Answer:
7.5 gallons
Step-by-step explanation:
Given:
The Thomas family went for a Sunday drive.
Before they left, Mr. Thomas noticed the gas tank was ¾ full.
When they returned home the gas tank was ⅓ full.
Total capacity of the gas tank = 18 gallons
<u>Question asked:</u>
How many gallons of gas did the car use on the drive?
<u>Solu</u>tion:
Before they left, quantity of gas in the tank = 
When they returned, quantity of gas in the tank = 
Quantity of gas used on the drive = 13.5 - 6 = 7.5 gallons
Therefore, 7.5 gallons of gas used on the drive by Thomas family.
Answer:
1) 8 : 343
2) 42.875 or 42 ⅞
3) 4 : 49
4) 16ft²
Step-by-step explanation:
Volume of cube: s³
Surface area of cube: 6s²
_____________________
32ft^3 and 1372ft^3 →
32 : 1372 = 8 : 343
343 / 8 = 42 ⅞ = 42.875
s³ → 6s²
s³ = 8, s = 2, s² = 4.
s³ = 343, s = 7, s² = 49.
These are proportional so it is already in the simplest ratio so it is not necessary to multiply by 6.
s³ → 8 : 343
6s² → 4 : 49
(4 / 49) × 196ft² = 16ft²
These calculations are based on the drawing of the file enclosed.
There are three right triangles.
From the big right triangle:
a^2 + b^2 = 25^2
From the small right triangle on the left side:
(25-x)^2 + 10^2 = a^2
From the small right triangle on the right side
x^2 +10^2 = b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = 25^2
=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2
=> x^2 -50x + 100 =0
Use the quadratic formular to find the roots:
x = 2.1 and x = 47.9
Distance from back: 25 - 2.1 = 22.9 ft
Answer: 22.9 ft
The formula for a parallelogram is A(area)= b(base) x h(height)
A= 6cm + 5cm
A= 11cm
A= 11cm x 12cm
A= 132cm
So your answer is 132cm.
