3x- 11 +59 = 90
3x + 48 = 90
3x +48-48 =90-48
3x = 42
3x/3 = 42/3
x= 14
<MNQ = 3x -11
<MNQ = 3(14)-11
<MNQ = 42-11
<MNQ = 31
Answer:
The correct answer is - 1/2 or 50% for first and second child to be affected.
Step-by-step explanation:
Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.
A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.
a cross between affected or dwarf and normal parent
Aa X aa
Punnett square:
a a
A Aa Aa
a aa aa
Aa- dwarfness
aa- normal height
The probability that both their first child and second child would have achondroplasia is
2/4 =1/2 or 50%.
Well, we can find the answer by multiplying the two fractions. 3/4*1/8 equals 3/32.
Answer:
b b.b b b b b b b b b b b b b b b b b b
Step-by-step explanation:
b b b
