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2 years ago

Might cut half my hair.

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

6 0

Yes do it it’s going to grow back real long

ycow [4]2 years ago

4 0

Answer:

well if you are a boy and don't like long hair then sure... but if you are a girl then don't cut... I mean I like long hairs... but it's your choice so.. ok

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There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror

RUDIKE [14]

Given:

Number of people bought tickets for comedy = $\frac{2}{5}$

Number of people bought tickets for horror = $\frac{1}{4}$

Number of people bought tickets for kids movie = $\frac{3}{10}$

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

Total number of tickets for comedy, horror and kids movie are = $(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )$

So,

$(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )$

LCM of 5,4,10 = 20

= $\frac{8+5+6}{20}$

= $\frac{19}{20}$

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = $1-\frac{19}{20}$

= $\frac{20-19}{20}$

= $\frac{1}{20}$

Hence,

The number of people who bought the tickets for action movie is $\frac{1}{20}$ .

7 0

3 years ago

How do u delete a post on here?

alukav5142 [94]

Answer:

You cant

Step-by-step explanation:

X=EAH Square uppercut 2

6 0

2 years ago

Read 2 more answers

Is 0.24 greater than 0.42?

natita [175]

Nope .42 is greater, .4 is closer to 1 then .2 have a great day and hope this helps

4 0

2 years ago

Read 2 more answers

Can you help me? Please

aksik [14]

x° = 60° (alternate angle)

Step-by-step explanation:

Hope it helps you!

4 0

2 years ago

If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta

Karo-lina-s [1.5K]

$\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad 
\begin{array}{llll}
\textit{now, hypotenuse is always positive}\\
\textit{since it's just the radius}
\end{array}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}$

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

$\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}
\\\\\\
\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b$

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means, -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-----------------------------\\\\
cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2
\\\\\\
cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}$

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}
\\\\\\
tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}
\\\\\\
tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}$

6 0

3 years ago