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Marat540 [252]
3 years ago
13

A scientist has a sample of the radioactive isotope bismuth-212. The isotope decays exponentially as shown in the table. Time (s

econds) Mass (grams) 10 26.8 20 23.9 30 21.3 40 19.0 50 16.9 60 15.1 Which equation best represents the curve of best fit for this set of data? A. f(x) = 29 • 0.989x B. f(x) = 27 • 1.011x C. f(x) = 30 • 0.989x D. f(x) = 28 • 0.234x
Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

f(x) = 30 • 0.989x

Step-by-step explanation:

Given the data :

10 26.8

20 23.9

30 21.3

40 19

50 16.9

60 15.1

Using technology, the exponential model equation obtained by plotting the data is :

y = 30.068(0.989)^x

Based on the general exponential formula :

y = ab^x

y = predicted value

Initial value, a = 30.068

Rate = b = 0.989

The most appropriate model equation from the options given is :

f(x) = 30 • 0.989^x

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Suppose that an individual has a body fat percentage of 19.3% and weighs 187 pounds. How many pounds of her weight is made up of
Hatshy [7]

Answer:

The individual has 36.09 pounds of body fat.

Step-by-step explanation:

Given that an individual has a body fat percentage of 19.3% and weighs 187 pounds, to determine how many pounds of her weight is made up of fat the following calculation must be performed:

(187 x 19.3) / 100 = X

3.609.1 / 100 = X

36.091 = X

Therefore, the individual has 36.09 pounds of body fat.

6 0
3 years ago
In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

5 0
3 years ago
What is the remainder for the synthetic division problem below?
Luden [163]

7 |1 -8 10
X. 7. -7
1 -1 3

A remainder is 3
7 0
2 years ago
Is my answer correct?
GalinKa [24]
Your answer is correct :)
3 0
3 years ago
Which expression matches the following: Jill scored 3 points for each of the 18 multiple
podryga [215]

Answer:18(3)

Step-by-step explanation:

8 0
3 years ago
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