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3 years ago

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Jeremy claims that if a linear function has a slope of the same steepness and the same y-intercept as the linear function in the

graph, then it must be the same function. On a coordinate plane, a line goes through points (0, negative 1) and (2, 0). Which equation is a counterexample to Jeremy’s argument? y = negative one-half x minus 1 y = negative one-half x + 1 y = one-half x minus 1 y = one-half x + 1

2 answers:

4vir4ik [10]3 years ago

7 0

Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

Step-by-step explanation:

Let us consider the general linear equation

Y = MX + C

On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).

Slope = ( 0 - -1)/( 2- 0) = 1/2

When x = 0, Y = -1

Substitutes both into general linear equation

-1 = 1/2(0) + C

C = -1

The equations for the coordinate is therefore

Y = 1/2X - 1

Let's check the equations one after the other

y = negative one-half x minus 1

Y = -1/2X - 1

y = negative one-half x + 1

Y = -1/2X + 1

y = one-half x minus 1

Y = 1/2X - 1

y = one-half x + 1

Y = 1/2X + 1

It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

GREYUIT [131]3 years ago

3 0

Answer:

The answer is A, y=-1/2x-1

Step-by-step explanation:

Got it correct on Edgenuity. ;)

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2 years ago

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2 years ago

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2 years ago

Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.

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Given:

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The fourth vertex of the parallelogram.

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Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

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Midpoint of AC = Midpoint of BD

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2 years ago