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3 years ago

Find the measures of the numbered angles in each figure

Mathematics

1 answer:

inessss [21]3 years ago

6 0

1 is 90o
2 is 90 - 27 = 63
3 63 angles 2 and 3 are in an isosceles triangle. They are opposite equal sides so the angles are equal.

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HELP ME PLEASE !!!!!!!!

Olenka [21]

Answer:35

Step-by-step explanation:

if you added 85,70, and 50 you would get 205 and that is more than the number of students that were interviewed so 35 would be the correct answer

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3 years ago

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For f(x) = -3x - 5, find f(-11). Explain what f(11) really means for the problem ?? Need this in like the next 4 hours please!!!

Verdich [7]

Answer:

for -11, 28. for 11, -38

Step-by-step explanation:

Typos in your question. can't tell if you need -11 or pos 11

-3(-11)-5 = 33-5= 28

-3(11)-5 = -33-5 = -38

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3 years ago

(0 - -3) x (1 + 5) divided by ( 2 - -2)

ElenaW [278]

Answer:

4.5

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3 years ago

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Which expressions represent the area of the entire shaded region, including the light and dark shading? select three options. 12

Alex Ar [27]

A triangle is a polygon. The total area of the figure can be represented by 12a, (6a+b), and 2b cm².

<h3>What is a triangle?</h3>

A triangle is a polygon with 3 sides and 3 vertices.

Since the area of a single triangle is a cm², and the shape is formed of 12 triangles, therefore, the area of the 12 triangles will be equal to,

$\text{Area of the complete figure} = 12 \times a = 12a\rm \ cm^2$

Given that the area of the complete dark portion is b cm², therefore, the area of the 6 triangles with a cm² of area each, and the black portion can be written as,

$\text{Area of the complete figure} = (6 \times a)+b = (6a+b)\rm \ cm^2$

As the dark portion also consists of 6 triangles with an area of a cm² each and the total sum of this dark area is b cm². Also, the light portion consists of 6 triangles with an area of a cm². Therefore, the total area can be written as,

$\text{Total area} = 6a+6a = b+b = 2b\rm\ cm^2$

Thus, the total area of the figure can be represented by 12a, (6a+b), and 2b cm².

Learn more about Triangles:

brainly.com/question/2773823

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2 years ago

Which equation could be used to find the zeros of the function f(x) = 6x2-11x-10 = 0 ? (x+2)(x-5) = 0 (3x+2)(2x-5) = 0 (x-10)

Alex Ar [27]

Answer:

(3x+2)(2x-5) = 0

Step-by-step explanation:

In the multiple choice options, all of the answers are in factored form. Factored from for quadratic equations are used to find the zeroes, when you equate each factor to 0.

Remember quadratic equations are in the form ax² + bx + c = 0.

Factor 6x² - 11x - 10 = 0:

I will use the <u>cross factors or "X"</u> method.

Write out the factors for "a" and "c" vertically (see diagram 1).

Test a pair of factors from "a" and a pair of factors from "c". Cross multiply them and add their products. If the sum of their products is "b", you found the factors.

The value of "b" is -11.

Example 1: (diagram 2)

I will try if the highlighted pairs of factors work. Multiply the pairs diagonally, which gives me "1" and "-60". The sum of "1" and "-60" is -59.

-59 is not -11; this is not the pair we want.

Example 2: (diagram 3)

Try another pair. Multiply 2*5=10 and 3*-2= -6. Add them together; -6 + 10 = 4.

4 is not -11; this is also wrong.

Example 3: (diagram 4)

Multiply 2*2=4 and 3*-5= -15.

Add the answers: 4 + (-15) = -11.

-11 is "b". Keep these factor pairs.

Find the factors: (diagram 5)

The factors are found by reading across the top and the bottom. Include "x" with the first factor.

(2x-5)(3x+2) = 0 or (3x+2)(2x-5) = 0

4 0

3 years ago