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Vilka [71]
3 years ago
13

Find the measures of the numbered angles in each figure

Mathematics
1 answer:
inessss [21]3 years ago
6 0
1 is 90o
2 is 90 - 27 = 63
3  63 angles 2 and 3 are in an isosceles triangle. They are opposite equal sides so the angles are equal.
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sleet_krkn [62]

Answer: B

Step-by-step explanation:

8 0
3 years ago
Help me please for brainliest!
UkoKoshka [18]

Answer:

1)option b

2)option a

Step-by-step explanation:

1) circumference = 62.8 in

=> 2πr= 62.8

=> r= 62.8/(2×3.14)= 10 in

diameter = 2×10 in = 20 in

2)diameter = 14m

radius = 7 m

Area of the circle= πr² =3.14(7)²=3.14×49

= 153.86

=153.9 m²

7 0
3 years ago
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How do I solve -2m=16m-9
Brums [2.3K]
-2m = 16m - 9

First, take '16m' from both sides.
-2m - 16m = -9
Second, add '-2m - 16m' to get '-18m'.
-18m = -9
Third, divide both sides by '-18'.
m =  \frac{-9}{-18}
Fourth, change the fraction into a negative.
m =  \frac{9}{18}
Fifth, find the GCF of 9 and 18.
The GCF is 9.
Sixth,  divide the numerator by the GCF.
9 ÷ 9 = 1
Seventh, divide the denominator by the GCF.
18 ÷ 9 = 2
Eighth, rewrite the fraction in simplest form.
m =  \frac{1}{2}

Answer as fraction: m =  \frac{1}{2}
Answer as decimal: m = 0.5
7 0
2 years ago
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Tank A has a capacity of 9.5 gallons. 6 1\3 gallons of the tank"s water are poured out. How many gallons of water are left in th
aleksandr82 [10.1K]

Answer:  Since 1/3 can't be turned into a decimal, change .5 into 1/2. In order to subtract, the fractions need a common denominator. The least common denominator is 6. So 1/3 turns into 2/6, and 1/2 turns into 3/6. Now you need to take 9 3/6 minus 6 2/6. The answer is 3 1/6 gallons of water.


Step-by-step explanation:


4 0
2 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
Read 2 more answers
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