Pleaaaaseeeeeee help!!!!!!!!!!!!!!!!!!!!! brainliest and 20 points
2 answers:
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Answer: The area of the parallelogram is:
_______________________________________________________
in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.
h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>
in) * (
<span> in) ;
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 = ;
Note: "23 ¼ " = [(23*4) + 1 ] / 4 = ;
____________________________________________________________
→ A = ( in) * ( in) ;
→ A =
in² = in² ;
→ A = (9393/8) in² =
→ A = in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________
_______________________________________________________
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________
b = 50.5 in.
h = 23.25 in.
____________________________________________________________
Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>____________________________________________________________
Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>
</span>___________________________________________________________
Note: "50 ½ " = [(50*2) + 1 ] / 2 =
Note: "23 ¼ " = [(23*4) + 1 ] / 4 =
____________________________________________________________
→ A = (
→ A =
→ A = (9393/8) in² =
→ A =
________________________________________________________
121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range
The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:
So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range
That's probably the answer they're looking for.