Answer:
0.0735,0.0179,0.7026
Step-by-step explanation:
Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.
Sample size = 49
Population mean = 78
Population std deviation = 28
Std error of sample mean = 
a)
: N(78, 4)
b) 
(by converting to Z and finding value from Z table)
c) P (x overbar less than or equals 69.6 )
=
d) P (75.8 less than x overbar less than 88 )
=
Answer: (10.66)(19.64) = 209.3624




<em>so it's equal to:</em>

<h3><em>
Hope I helped you!</em></h3><h3><em>
Success!</em></h3>
<em>by a random romanian guy</em>
Answer:
1/5 :)
Step-by-step explanation:
The answer is 300. I hope that helped!