Question

Suppose a simple random sample of size nequals49 is obtained from a population with mu equals 78 and sigma equals 28.

Answer 1

Answer:

0.0735,0.0179,0.7026

Step-by-step explanation:

Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.

Sample size = 49

Population mean = 78

Population std deviation = 28

Std error of sample mean = $\frac{\sigma}{\sqrt{n} } \\=4$

a) $\bar x$: N(78, 4)

b) $P(\bar x >83.8)\\=0.0735$

(by converting to Z and finding value from Z table)

c) P (x overbar less than or equals 69.6 )​

=$P(\bar x \leq 69.6)\\=0.0179$

d) P (75.8 less than x overbar less than 88 )

=$P(75.8$