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Basile [38]
4 years ago
14

Suppose a simple random sample of size nequals49 is obtained from a population with mu equals 78 and sigma equals 28.

Mathematics
1 answer:
VLD [36.1K]4 years ago
4 0

Answer:

0.0735,0.0179,0.7026

Step-by-step explanation:

Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.

Sample size = 49

Population mean = 78

Population std deviation = 28

Std error of sample mean = \frac{\sigma}{\sqrt{n} } \\=4

a) \bar x: N(78, 4)

b) P(\bar x >83.8)\\=0.0735

(by converting to Z and finding value from Z table)

c) P (x overbar less than or equals 69.6 )​

=P(\bar x \leq 69.6)\\=0.0179

d) P (75.8 less than x overbar less than 88 )

=P(75.8

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