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enyata [817]
3 years ago
13

(-6time + 3) + (5time -4)

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

-2

Step-by-step explanation:

18+-20

-2

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Answer: x = -2
Steps/work provided down below. Please let me know if you have any further questions! :)

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A movie theater sells adult tickets and child tickets. • Each adult ticket costs $7.25. • Each child ticket costs $6.50. Which e
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Question is on the picture !
Nataly [62]

Answer: 122.5

======================================================

Explanation:

First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.

The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x

(perimeter of A)/(perimeter of B) = 7/2

x/35 = 7/2

x*2 = 35*7 .... cross multiply

2x = 245

2x/2 = 245/2 .... divide both sides by 2

x = 122.5

The perimeter of figure A is 122.5

4 0
3 years ago
Plz help me solve it step by step (find the the area)
dexar [7]

Answer:

Step-by-step explanation:

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4 0
3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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