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3 years ago

Properties of a circle theorem

Mathematics

1 answer:

lukranit [14]3 years ago

3 0

Answer: These might be some properties :

The angle in a semicircle is a right angle.

Angles in the same segment are equal.

Opposite angles in a cyclic quadrilateral sum to 180°

Step-by-step explanation:

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What do you need to know?

cupoosta [38]

Answer:

incorrect

Step-by-step explanation:

the volume of a cube = s³ ( where s is the length of the side )

to find s take the cube root

s = $\sqrt[3]{27}$ = 3

since 3 × 3 × 3 = 27

4 0

3 years ago

3 times the first of three consecutive odd integers is 3 more than twice the third? what is the third integer

fenix001 [56]

Answer:

Step-by-step explanation:

The difference between consecutive integers is 1.

The difference between consecutive odd integers is 2.

Let the smallest odd integer be x.

Then the next greater one is x + 2. The greatest one is x + 4.

"3 times the first" is 3x

"twice the third" is 2(x + 4)

"3 times the first of three consecutive odd integers is 3 more than twice the third"

3x = 2(x + 4) + 3

3x = 2x + 8 + 3

x = 11

The smallest integer is 11.

x + 4 = 11 + 4 = 15

The greatest one is 15.

4 0

3 years ago

35 POINTS PLEASE HURRY!!!!!

andreyandreev [35.5K]

Answer:

where is the question m8

Step-by-step explanation:

8 0

2 years ago

Figure this out please Asap.

weeeeeb [17]

If the polygons are similar then the sides are in proportion.

$\dfrac{32}{24}=\dfrac{32:8}{24:8}=\dfrac{4}{3}$

Therefore we have the equations:

$\dfrac{x-1}{6}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(x-1)=(4)(6)\\\\3x-3=24\qquad\text{add 3 to both sides}\\\\3x=27\qquad\text{divide both sides by 3}\\\\\boxed{x=9}$

$\dfrac{y+1}{21}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(y+1)=(21)(4)\\\\3y+3=84\qquad\text{subtract 3 from both sides}\\\\3y=81\qquad\text{divide both sides by 3}\\\\\boxed{y=27}$

6 0

3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$