A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
2 answers:
Answer: 362880
Step-by-step explanation:
Given : A contractor wishes to build 9 houses, each different in design.
he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side.
Choices to arrange first lot = 9
After first house is designed , Choices to arrange second lot = 8
After second house is designed , Choices to arrange third lot = 7
and so on.....
So the total number of ways to arrange 9 lots will be :-
Hence, the required number of ways =362880
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Circle A is missing, so i have attached it.
Answer:
∠XYZ = 35°
Step-by-step explanation:
We want to find the angle ∠XYZ in the image attached.
To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;
∠XYZ = ½(arc WZ - arc XZ)
From the image, arc WZ = 175° and arc XZ = 105°
Thus;
∠XYZ = ½(175 - 105)
∠XYZ = ½(70)
∠XYZ = 35°
