A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
2 answers:
Answer: 362880
Step-by-step explanation:
Given : A contractor wishes to build 9 houses, each different in design.
he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side.
Choices to arrange first lot = 9
After first house is designed , Choices to arrange second lot = 8
After second house is designed , Choices to arrange third lot = 7
and so on.....
So the total number of ways to arrange 9 lots will be :-
Hence, the required number of ways =362880
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Answer:
Tina would save the same amount using either option after 20 months.
With either option, Tina would save $700.
Step-by-step explanation:
This problem can be modeled by a first order equation:
Where Tina's saved money after n months is:
S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.
The first option is to put $500 away initially and save $10 every month, so:
The second option is to put $100 away initially and save $30 every month, so:
After how many months would Tina save the same amount using either option?
It will happen at the month n in which , so:
500 + 10n = 100 + 30n
500 - 100 = 30 - 10n
400 = 20n
20n = 400
n = 20.
Tina would save the same amount using either option after 20 months.
How much would she save with either option?
We can choose or
, since they are equal
With either option, Tina would save $700.