A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
2 answers:
Answer: 362880
Step-by-step explanation:
Given : A contractor wishes to build 9 houses, each different in design.
he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side.
Choices to arrange first lot = 9
After first house is designed , Choices to arrange second lot = 8
After second house is designed , Choices to arrange third lot = 7
and so on.....
So the total number of ways to arrange 9 lots will be :-
Hence, the required number of ways =362880
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Answer:
Step-by-step explanation:
The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is .
The area of a triangle is given by . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be
and intersect at a
angle.
Thus, the sum of all four triangles is .
Therefore, the area of the window is: