A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
2 answers:
Answer: 362880
Step-by-step explanation:
Given : A contractor wishes to build 9 houses, each different in design.
he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side.
Choices to arrange first lot = 9
After first house is designed , Choices to arrange second lot = 8
After second house is designed , Choices to arrange third lot = 7
and so on.....
So the total number of ways to arrange 9 lots will be :-
Hence, the required number of ways =362880
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16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32
= 32 x 2 = 
50 x 2
= 64 : 2 = 32 %
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32
50 x 2
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.