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3 years ago

12

Which galaxy is the farthest from Earth?galaxy agalaxy bgalaxy cgalaxy d

1 answer:

harina [27]3 years ago

5 0

Galaxy c is the farthest

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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks. Today's cafeteria s

kobusy [5.1K]

Answer:

Equation 1: 14t + 61s = 150

Equation 2: 14t + 25s = 78

Use Elimination (x)

(-1) (14t + 25s) = (78) (-1)

-14t - 25s = -78

14t + 61s = 150

+ -14t - 25s = -78

--------------------------

36s = 72

s = 2

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Then find t

14t + 61(2) = 150

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Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

<u>Part A)</u> $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

<u>the answer Part A is</u>

$9-----> A$

<u>Part R)</u> $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

<u>the answer Part R is</u>

$14-----> R$

<u>Part Y)</u> $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

<u>the answer Part Y is</u>

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

<u>the answer Part S is</u>

$23-----> S$

<u>Part O)</u> $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

<u>the answer Part O is</u>

$17-----> O$

<u>Part E)</u> $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

<u>the answer Part E is</u>

$3-----> E$

<u>Part I)</u> $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

<u>the answer Part I is</u>

$20-----> I$

<u>Part D)</u> $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

<u>the answer Part D is</u>

$10-----> D$

<u>Part W)</u> $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

<u>the answer Part W is</u>

$18-----> W$

<u>Part E)</u> $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

<u>the answer Part E is</u>

$7-----> E$

<u>Part T)</u> $0.5(4a+10)=2a+$

Using the distributive property

<u>Part T)</u> $0.5(4a+10)=2a+5$

therefore

<u>the answer Part T is</u>

$1-----> T$

<u>Part R)</u> $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

<u>the answer Part R is</u>

$6-----> R$

<u>Part O)</u> $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

<u>the answer Part O is</u>

$13-----> O$

<u>Part T)</u> $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

<u>the answer Part T is</u>

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

<u>the answer Part W is</u>

$16-----> W$

<u>Part H)</u> $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

<u>the answer Part H is</u>

$2-----> H$

<u>Part E)</u> $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

<u>the answer Part E is</u>

$11-----> E$

Part A) $bu+uv=\ (b+v)$

$bu+uv=u(b+v)$

therefore

<u>the answer Part A is</u>

$5-----> A$

<u>Part F)</u> $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

<u>the answer Part F is</u>

$12-----> F$

<u>Part M)</u> $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

<u>the answer Part M is</u>

$8-----> M$

<u>Part S)</u> $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

<u>the answer Part S is</u>

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

<u>the answer Part T is</u>

$15-----> T$

<u>Part R)</u> $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

<u>the answer Part R is</u>

$19-----> R$

<u>the answer is</u>

they are made for two wrists

4 0

4 years ago

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