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4 years ago

Any ordered pair that makes all equations in a system of equations true is a(n) ...?

Mathematics

1 answer:

timurjin [86]4 years ago

3 0

That ordered pair is a solution to the equation system.

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As x approaches positive infinity, which of the following describes the end behavior for

k0ka [10]

Answer:

c. hope helpful answer to your question

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3 years ago

For which value of m is the equation below true? x^m x^4=x^8? A m=4. B m=12. C m=32. D m=2

Karolina [17]

Answer:

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{m+n}$ , thus

Given

$x^{m}$ × $x^{4}$ = $x^{8}$ , that is

$x^{4+m}$ = $x^{8}$

Since the bases are the same equate the exponents

4 + m = 8 ( subtract 4 from both sides )

m = 4 → A

5 0

3 years ago

1. Solve for y=. 6 + 2y = 12.

Dimas [21]

Answer:

y=3

Step-by-step explanation:

8 0

3 years ago

Anne and Andy sell pizza by the slice. Anne made 7 pizzas, and sold 5/12 of each pizza. Andy made 5 pizzas, and sild 7/12 of eac

gulaghasi [49]

Answer:

No, they both sold equal amount of pizza

Step-by-step explanation:

In this question, we are concerned with knowing who sold more pizza between Anne and Andy.

Let’s have what each individual sold then make a comparison.

Anne made 7 and sold 5/12 of each. Total of what was sold by Anne would be 7 * 5/12 = 35/12

Andy made 5 and sold 7/12 of each. Total sold by Andy would be 5 * 7/12 = 35/12

Looking at the answers we can see that they are equal to same 35/12. This means they both sold equal amount of pizza

6 0

3 years ago

A worker has job offers from two companies. The information below summarizes the job offer from each company.Company A:Starting

Zanzabum

Using linear functions, we have that:

For Company A: $S_A(n) = 31000 + 3000n$

For Company B: $S_B(n) = 38000 + 2000n$

B. The salaries will be the same after 7 years.

A linear function is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the initial value.

Item a:

For Company A, the salary starts at $31,000, with a raise of $3,000 each year. Thus, $b = 31000, m = 3000$ , and the salary after n years is given by:

$S_A(n) = 31000 + 3000n$

For Company B, the salary starts at $38,000, with a raise of $2,000 each year. Thus, $b = 38000, m = 2000$ , and the salary after n years is given by: